Find the two numbers whose sum is54 and whose difference is 4

2 answers:

7 0

Sum of 54: X + Y = 54
Difference is 4: X - Y = 4

Solve for one variable first.

X = 4 + y (rewritten from second equation)

Now plug into the first equation for x

4 + y + y = 54
4 + 2y = 54 (subtract 4)
2y = 50 (divide by 2)
Y = 25

Now use Y to solve for X

X - 25 = 4 (add 25 on each side)
X = 29

harkovskaia [24]2 years ago

4 0

Answer: I can not see the picture

Step-by-step explanation:

can you show it?

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If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$