The answer is: " biogeography " .
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The given data is Magnification, M = 15
Length of the tube , L = 16 cm
The focal length of the lens can be calculated by:
M = L/F
Substituting the value, we get:
15 = 16/f
f = 16/15
f = 1.067 cm
Using the equation of magnification we get,
M = v/u
Substituting the values we get:
15 = v/u
v = 15 u
With the help of lens formula, calculate the object distance:
1/f = 1/v + 1/u
Substituting the value we get,
1/1.067 = 1/15u + 1/u
0.937 = 1.067/u
u = 1.13 cm or 1.1 cm.
Hence, the object distance is 1.1 cm.
The answer to your question is Vegetative Propagation.
Vegetative Propagation is defined as a form of asexual reproduction of a plant. It occurs when only one "parent plant" is involved in producing an offspring that will be genetically identical to the parent.
