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Snowcat [4.5K]
2 years ago
14

g A bowl contains 5 white balls, 10 red balls, and 15 blue balls. You are to randomly select two balls without replacement. You

will draw one ball (and keep it outside of the bowl) and then you will draw a second ball. The second ball you select is red, what is the probability that the first one was white
Mathematics
1 answer:
qaws [65]2 years ago
4 0

We want to find the probability of getting a red ball in our first draw, given that in the second draw we got a white ball.

We will get P = 0.345

We know that the bowl has:

  • 5 white balls
  • 10 red balls
  • 15 blue balls.

For a total of 30 balls.

We draw a ball and we store it.

Then we draw another ball and we see that it is a white ball.

We want to get the probability that the first ball was red.

The only thing we know, is that one of the white balls can be taken out of the sample space, because we can only draw it second if we did not draw it on the first attempt.

Then we can think that we have:

  • 4 white balls.
  • 10 red balls
  • 15 blue balls.

For a total of 29 balls.

Then the probability of getting a red one is just the quotient between the number of red balls and the total number of balls, we will get:

P = 10/29 = 0.345

If you want to learn more, you can read:

brainly.com/question/11234923

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Answer:

Step-by-step explanation:

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5x² -  16 = 8x + 5

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