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Sholpan [36]
3 years ago
11

What is the equation of a line that is perpendicular to the y-axis and goes through point (-1,-8).​

Mathematics
1 answer:
Wittaler [7]3 years ago
4 0
Y= -1

it’s a horizontal line that is perpendicular to the y-axis
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Which shows the equation below written in the form ax2 + bx + c = 0?
Svetach [21]

Answer:

A

Step-by-step explanation:

X^2 + 6X + 8 =3

TRANSPOSE 3 TO LEFT

X^2 + 6X + 8 - 3 = 0

CALCULATE

X^2 + 6 X + 5 = 0

3 0
3 years ago
Which of the following situations could be represented by the expression - 14+ (- 7)?
RUDIKE [14]

Answer:

Matt's

Step-by-step explanation:

he has to give away $14 (-14)

and also $7 (-7)

The others have positive numbers.

4 0
3 years ago
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

6 0
3 years ago
Hi could someone just help me with this I'm not sure if i'm doing it correctly.
salantis [7]
Two angles are supplementary when they <span>add up to 180 degrees </span>⇒
m∠1 + m∠2 = 180°
4y + 7 + 9y + 4 = 180
13y + 11 = 180
13y = 180 - 11
13y = 169
y = 169/13
y = 13

m∠2 = 9y + 4 = 9 * 13 + 4 = 121°
4 0
3 years ago
Cj your a goat for this lol HELP
3241004551 [841]

Answer:

>  

Step-by-step explanation:

brainliest please?

4 0
3 years ago
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