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barxatty [35]
3 years ago
6

Evaluate the expression for x = 2 and y = 4 16x^(0 +2x^(2* y^(-1)))

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

47

Step-by-step explanation:

When an expression is evaluated, the expression is either simplified or calculated.

The result of the expression is 47

The expression is given as:

Where:

x = 2 and y = 4

Substitute 2 for x and 4 for y in the expression

So, we have:

Evaluate all exponents

Evaluate all products

Evaluate like terms

Hence, the result of the expression is 47

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Prove algebraically that (m + 2)2 – m 2 – 12 is always a multiple of 4
Julli [10]

Answer:

(m + 2)^{2} - m^{2}  - 12 = 4(m - 2)

Step-by-step explanation:

Step 1:

Write the expression

(m+2)^{2} - m^{2}  - 12

Step 2: Expand (m + 2)^{2}

(m+2)^{2} - m^{2} - 12\\(m+2)(m+2) - m^{2}  - 12\\m^{2} + 2m + 2m + 4 - m^{2}  - 12

Step 3: Collect similar terms

m^{2}  - m^{2}  + 4m + 4 - 12\\4m - 8

Step 4: Factor 4 out of the expression to prove that the expression is a multiple of 4.

Therefore\\4m - 8 = 4(m - 2)\\Hence,\\(m+2)^{2}  - m^{2} -  12 is a multiply of 4 because the expression is equal to 4(m-2)

3 0
3 years ago
Can you please help me with this
Vitek1552 [10]

Answer:

log9

Step-by-step explanation:

Using the rules of logarithms

logx + logy = log(xy)

logx - logy = log(\frac{x}{y})

logx^{n} ⇔ nlogx

Given

2(log18- log3) + \frac{1}{2}log\frac{1}{16}

= 2(log(\frac{18}{3} ) ) + log(\frac{1}{16}) ^{\frac{1}{2} }

= 2log6 + log\frac{1}{4}

= log6² + log\frac{1}{4}

= log36 + log\frac{1}{4}

= log( 36 × \frac{1}{4} )

= log9

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