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3 years ago

Find the measure of each equalateral triangle if AB=2x ,BC=x+7 ,CA=4x-14

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

3 0

Answer:

X = 7

AB = 14

BC = 14

CA = 14

Step-by-step explanation:

This is an equilateral triangle so you can set the lengths equal to each other in order to find X.

2x=x+7

-x -x

x=7

you can do this with any combination of the lengths and you will always get 7

Now you plug in 7 for x

Original: 2x

Plug in 7: 2*7

You get 14

Since this is after all, an equilateral triangle all lengths are equal so all lengths are 14.

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What is 1 3\4 + 2 2/3

cricket20 [7]

Hello!

Answer:

4 5/12

*The answer must have a whole number and a fraction.*

Step-by-step explanation:

Lesson: Adding Fractions

First, you add by the whole number.

$1+2=3$

Then you combine by the fraction or number.

$\frac{3}{4}+\frac{2}{3}=\frac{17}{12}$

$3+\frac{17}{12}$

Next, you convert improper fraction into the mixed numbers.

$\frac{17}{12}=1\frac{5}{12}$

$3+1\frac{5}{12}$

And finally, add by the numbers.

$3+1=4$

Final answer: → $4\frac{5}{12}$

Hope this helps!

Thanks!

Have a great day!

-Charlie

3 0

3 years ago

How many numbers are between 200 and 400 that begin or end with 3 explain how you got it please

GuDViN [60]

Removed. I made a mistake haha and someone made the correct one :)

3 0

3 years ago

Read 2 more answers

I don’t understand this subject at all if you wold answer that would be a big help

Digiron [165]

Answer:

d= 8.6 ft

Step-by-step explanation:

In similar triangles, the corresponding sides are in proportion.

$\boxed{\dfrac{AW}{MZ}=\dfrac{AJ}{MJ}=\dfrac{WJ}{ZJ}}$

To find the value of x,

$\dfrac{AJ}{MJ}=\dfrac{WJ}{ZJ}\\\\\\\dfrac{6}{7}=\dfrac{d}{10}\\\\\\\dfrac{6}{7}*10=d$

d = 8.6 ft

4 0

2 years ago

It's 16inches tall and the exact model is 40 feet long

OleMash [197]

Ahh... this is pretty easy!!
.
Locomotive is 40 feet.
.
Model is 16.
.
So?
.
Divide 40 by 16!!
.
What's that?
.
2.5.
.
So your answer choice is 2.5
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Hope I helped!!

4 0

3 years ago

A restaurant offers a $12 dinner special that has 77 choices for an appetizer, 1010 choices for an entrée, and 44 choices for

krok68 [10]

280 I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre, so the number of possible meals to this point is n = 7 * 10 = 70 Finally, you finish off with a dessert, so the number of meals is: n = 70 * 4 = 280 Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is n = 77 * 1010 * 44 = 3421880 But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.

5 0

3 years ago