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3 years ago

MORE PINTS LOLOLOLOLOOLOLLOLOLOLOLOLOLOLOLO

Mathematics

2 answers:

kherson [118]3 years ago

7 0

Answer:

Thank You So Much and God Bless You !!!

vladimir2022 [97]3 years ago

4 0

Answer:

mmm

Step-by-step explanation:

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(1) Cos AcosecA=cot A

Mashutka [201]

Answer:

The Basic Identities are :

$cosec(A) = \frac{1}{ \sin(A) }$

$\tan(A) = \frac{ \sin(A) }{ \cos(A) }$

$\cot(A) = \frac{1}{ \tan(A) } = \frac{ \cos(A) }{ \sin(A) }$

So for this question :

$\cos(A)cosec(A) = \cot(A)$

$l.s.h = \cos(A) \times \frac{1}{ \sin(A) }$

$l.s.h = \frac{ \cos(A) }{ \sin(A) }$

$l.sh = \cot(A) \: (proven)$

7 0

3 years ago

an airline experiences a no show rate of 6%. what is the maximum number of reservations that it could accept for a flight with a

Alborosie

168 passengers because 168*95%=159.6

Therefore 168 passengers would have to book the flight

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3 years ago

Which of the following is not an undefined term? point, ray, line, plane

Goshia [24]

Answer:

Step-by-step explanation:

Ray

5 0

3 years ago

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

How do I solve this?

Aleksandr-060686 [28]

First you have to set up your equation. 5x+80 and x+15.

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3 years ago

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