3 years ago

Help pls!! #420hehsh

Mathematics

1 answer:

ZanzabumX [31]3 years ago

5 0

Answer:

It's gonna be probably A

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The olympics are held every four years. In 2016, the XXXI olympiad were held in Rio de Janeiro,Brazil. Determine the year of the

Anna007 [38]

Answer:

First Olympic held in year 1896.

Step-by-step explanation:

Number of Olympiad held in Rio = XXXI = 31st

Difference of years in two consecutive Olympiads = 4 years

Number of years spent in 31 Olympiads can be calculated by,

Number of years spent = (n - 1)d

Here n = number of Olympiads held

d = difference between two consecutive Olympiads

Number of years spent till 31st Olympiads = (31 - 1)×4

= 120 years

Therefore, 1st Olympiad held in the year = 2016 - 120

= 1896

6 0

3 years ago

Help with this pls and thank u

stira [4]

Answer:

where is the question plsss tell me what you ask

8 0

3 years ago

Drag numbers to complete the table for missing values of x, x2, x3

tresset_1 [31]

Top row is x= 10, x^2 =100, x^3 = 1000
Bottom row is 5, 25, 125

5 0

4 years ago

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A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

$V = x^2h cm^3$

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

$V = 2xh(dx/dt)+ x^2(dh/dt)$

Substituting the given values , we will get

$[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)$ [/tex]

$dV/dt = -288+144 = -144cm^3/min$

So at that moment, the volume is decreasing at the rate of

$144 cm^3/min$

4 0

3 years ago

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I need to know the percent!

Anton [14]

6/12=1/2
Therefore 6/12 is equal to 50/100 or 50%

4 0

4 years ago

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