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sasho [114]
3 years ago
11

Determine the slope and y-intercept of a line that passes through the points (-2, 6) and

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

Answer:

y = \frac{-3}{2}x + 3

Step-by-step explanation:

Step 1 - Calculate slope first via the equation:

\frac{y2 - y1}{x2 - x1}

Where x1 and y1 are the coordinates of the first set whereas x2 and y2 are the second set. Plug the variables in:

\frac{6 - (-3)}{-2 - 4} \\\frac{6 + 3 )}{-2 - 4} \\\frac{9}{-6}

Which simplifies to:

\frac{3}{-2}

Now, in the line equation form we know x:

y = mx + c

y = \frac{3}{-2}x + c

Step 2 - Calculate y intercept

Plug the variables of one point into the above equation:

y = \frac{3}{-2}x + c

6 = \frac{3}{-2}(-2) + c

6 = \frac{3}{-2}(-2) + c \\6 = 3 + c\\6 - 3 = c\\c = 3\\

Meaning that the full line equation is:

y = \frac{-3}{2}x + 3

Hope this helps!

Andrei [34K]3 years ago
3 0

Answer:

Y = 3

Step-by-step explanation:

Y = -3/2x +3

Y = -3/2 × 0 + 3

Y = 3

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