Let t=number of years since 1991.
Then
P(t)=147 e^(kt) ... in millions
P(0)=147 e^(0)=147
P(7)=147 e^(7k)=153
e^(7k)=(153/147)
take ln both sides
ln(e^(7k))=ln(153/147)
7k=0.0400 => k=0.005715
Year 2017=>t=2017-1991=26
P(26)=147e^(26*.005715)=170.55
Answer: in 2017, the projected population is 170.55 millions.
Answer:
Step-by-step explanation:
Given that the population of a city increased steadily over a ten-year span. The following ordered pairs show the population x and the year y over the ten-year span in the form (x, y) for specific recorded years.
x y
2500 2001
2650 2002
3000 2004
3500 2007
4200 2011
Slope 0.005865485
Intercept 1986.406413
So regression line is
When population = 15000
The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:
93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x
Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y
Hope this helps!
Answer:
64-63=1 so she drove 1 extra miles the second month
Step-by-step explanation:
Answer:
Runner B
Step-by-step explanation:
speed = distance ÷ time
Runner A: 1 ÷ 8 = 0.125m/ms
Runner B: 2 ÷ 10 = 0.2m/ms
Runner C: 3 ÷ 20 = 0.15m/ms
Runner D: 5 ÷ 30 = 0.17m/ms
Runner B has the highest speed so he is the fastest runner.
