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aliya0001 [1]
3 years ago
11

0.4•(-0.03) plz help

Mathematics
2 answers:
Lena [83]3 years ago
4 0

Answer: -0.012

Step-by-step explanation:

Vesna [10]3 years ago
3 0

Answer:

-0.012

Step-by-step explanation:

69420nice

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What is the inequality shown?
ale4655 [162]

Answer:

1 is inequality

replace the value were _2.

8 0
3 years ago
12% of children are nearsighted, but this condition often is not detected until they go to kindergarten. A school district tests
Klio2033 [76]

Answer:

There is a 34.60% probability that 0 or 1 of them is nearsighted.

Step-by-step explanation:

For each children, there are only two possible outcomes. Either they are nearsighted, or they are not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that p = 0.12.

A school district tests all incoming kindergarteners' vision. In a class of 18 kindergarten students, what is the probability that 0 or 1 of them is nearsighted?

There are 18 students, so n = 18

This probability is:

P = P(X = 0) + P(X = 1)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.12)^{0}.(0.88)^{18} = 0.1002

P(X = 1) = C_{18,1}.(0.12)^{1}.(0.88)^{17} = 0.2458

So

P = P(X = 0) + P(X = 1) = 0.1002 + 0.2458 = 0.3460

There is a 34.60% probability that 0 or 1 of them is nearsighted.

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3 years ago
What quadrant does -495 lie in?
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A(5−x)=bx−8 what is x
nata0808 [166]

5a+8 /a+b  is the answer.



 


6 0
3 years ago
Read 2 more answers
SOMEONE HELP PLEASE
yan [13]
I have this same question, can anyone answer it?
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4 years ago
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