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Nimfa-mama [501]
2 years ago
12

EASY BRAINLIEST PLEASE HELP!!

Mathematics
2 answers:
ivolga24 [154]2 years ago
6 0
I may be wrong but I am pretty sure it is a parallelogram
katovenus [111]2 years ago
3 0

Answer:

i think it's a quadrilateral it's a rhombus.

Step-by-step explanation:

hope this helps

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Write as a polynomial: <br><br> 2a^2(a-1)(3-a)
seropon [69]

Answer:

-2a^4+8a^3-6a^2

Step-by-step explanation:

2a^2(a-1)(3-a)

2a^2(-a^2 +3a-3+a)

2a^2(-a^2+4a-3)

-2a^4+8a^3-6a^2

6 0
2 years ago
How many quarts in a gallon
sukhopar [10]
4 quarts are in a single gallon
7 0
3 years ago
Read 2 more answers
Solve the system of equations by substitution. 3/8x + 1/3y = 17/24
VashaNatasha [74]

Answer:

this question is not complete. need another equation

Step-by-step explanation:

give another equation then I can solve

\frac{3}{8} x =  \frac{17}{24}  -  \frac{1}{3} y \\ x =  \frac{17}{9}  -  \frac{8}{9} y

7 0
3 years ago
An article reports the following data on yield (y), mean temperature over the period between date of coming into hops and date o
skelet666 [1.2K]

Answer:

x1=c(16.7,17.4,18.4,16.8,18.9,17.1,17.3,18.2,21.3,21.2,20.7,18.5)

x2=c(30,42,47,47,43,41,48,44,43,50,56,60)

y=c(210,110,103,103,91,76,73,70,68,53,45,31)

mod=lm(y~x1+x2)

summary(mod)

R output: Call:

lm(formula = y ~ x1 + x2)

Residuals:  

   Min      1Q Median      3Q     Max

-41.730 -12.174   0.791 12.374 40.093

Coefficients:

        Estimate Std. Error t value Pr(>|t|)    

(Intercept) 415.113     82.517   5.031 0.000709 ***  

x1            -6.593      4.859 -1.357 0.207913    

x2            -4.504      1.071 -4.204 0.002292 **  

---  

Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1  

Residual standard error: 24.45 on 9 degrees of freedom  

Multiple R-squared: 0.768,     Adjusted R-squared: 0.7164  

F-statistic: 14.9 on 2 and 9 DF, p-value: 0.001395

a).  y=415.113 +(-6.593)x1 +(-4.504)x2

b). s=24.45

c).  y =415.113 +(-6.593)*21.3 +(-4.504)*43 =81.0101

residual =68-81.0101 = -13.0101

d). F=14.9

P=0.0014

There is convincing evidence at least one of the explanatory variables is significant predictor of the response.

e).  newdata=data.frame(x1=21.3, x2=43)

# confidence interval

predict(mod, newdata, interval="confidence")

#prediction interval

predict(mod, newdata, interval="predict")

confidence interval

> predict(mod, newdata, interval="confidence",level=.95)

      fit      lwr      upr

1 81.03364 43.52379 118.5435

95% CI = (43.52, 118.54)

f).  #prediction interval

> predict(mod, newdata, interval="predict",level=.95)

      fit      lwr      upr

1 81.03364 14.19586 147.8714

95% PI=(14.20, 147.87)

g).  No, there is not evidence this factor is significant. It should be dropped from the model.

4 0
2 years ago
Solve for x; y=mx+b I can find x by_______________ on both sides of the equation PLZ Show your Work Thank You
amid [387]

Answer:

"subtracting b, then dividing by m"

Step-by-step explanation:

To solve for a particular variable, look a the operations that are being performed on that variable. Then "undo" those operations in reverse order.

Here, the operations done to x are ...

• multiply by m

• add b to the product

Using the above recipe, first we "undo" the additon of b. We accomplish that by subtracting b from both sides of the equation. This gives ...

y - b = mx + b - b

y - b = mx . . . . . . . . . simplify

Next, we "undo" the multiplicatin by m. We accomplish that by dividing both sides of the equation by m.

(y -b)/m = mx/m

(y -b)/m = x . . . . . . . . simplify

This is your solution for x:

x = (y - b)/m

We found it by subtracting b, then dividing by m on both sides of the equation.

6 0
3 years ago
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