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joja [24]
3 years ago
8

Find the solution for x when x^2=0.09

Mathematics
2 answers:
Brut [27]3 years ago
7 0
X=-3/10 for the first x. X=3/10 for the second x.
Lubov Fominskaja [6]3 years ago
6 0

Answer:

x = 0.3

Step-by-step explanation:

x=\sqrt{0.09},\:x=-\sqrt{0.09}\quad

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Can somebody please help me with 3 and 5. Please don’t answer if you are not sure. 17 points
otez555 [7]
The Pyth. Thm. tells us the following:  (hypo)^2 = (leg 1)^2 + (leg 2)^2.
Here the hypo is 75 miles.  One train traveled x miles and the other x+10 miles.

applying the Pyth. Thm., 

x^2 + (x+10)^2 = 75^2

which becomes   x^2 + x^2 + 20x + 400 = 5625, or
                               2x^2 + 20x - 5225 = 0.

Choose a method easy for you that will lead to a solution (x-value).
Using "completing the square," I obtained x= 47.8 miles and x = 57.8 miles.  I

It's very important to check one's work.  Suppose x = 47.8 miles.  Then x+10 = 57.8 miles.

47.8^2 + 57.8^2 = 75^ must be true.  Is it?

2284.84 + 3340.84           5625
          5625.6      is approx equal to 5625.  Close enough.

The first train traveled 47.8 miles and the second 57.8 miles.
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=8%5Csqrt%7B0.01%7D" id="TexFormula1" title="8\sqrt{0.01}" alt="8\sqrt{0.01}" align="absmiddle"
Harman [31]

8 * 0.1

Answer: 0.8


Hope this helps.

5 0
3 years ago
The diameter of a sphere is 4 centimeters. which represents the volume of the sphere?
amid [387]
The volume of a sphere with respect to its diameter is:

V=(4πr^3)/3

V=(πd^3)/6  (because r=d/2 and r^3=(d^3)/8), we are given that d=4 so

V=64π/6 cm^3

V=32π/3 cm^2

V≈33.51 cm^3  (to nearest hundredth)
3 0
4 years ago
I don't know what to do.
zalisa [80]
U gotta subtract all of the numbers 
8 0
3 years ago
Read 2 more answers
Three forces act on an object. Two of the forces are at an angle of 95◦ to each other and have magnitudes 35 N and 7 N. The thir
Cerrena [4.2K]

We want to find \vec F_4 such that the object needs is in equilibrium:

\vec F_1+\vec F_2+\vec F_3+\vec F_4=\vec0

We're told that F_1=35\,\mathrm N, F_2=7\,\mathrm N, and F_3=9\,\mathrm N. We also know the angle between \vec F_1 and \vec F_2 is 95º, which means

\vec F_1\cdot\vec F_2=F_1F_2\cos95^\circ=245\cos95^\circ

\vec F_3 is perpendicular to both \vec F_1 and \vec F_2, so \vec F_1\cdot\vec F_3=\vec F_2\cdot\vec F_3=0.

If we take the dot product of \vec F_1 with the sum of all four vectors, we get

\vec F_1\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\vec F_1\cdot\vec F_1+\vec F_1\cdot\vec F_2+\vec F_1\cdot\vec F_3+\vec F_1\cdot\vec F_4=0

{F_1}^2+\vec F_1\cdot\vec F_2+0+\vec F_1\cdot\vec F_4=0

\implies\vec F_1\cdot\vec F_4=-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)

We can do the same thing with \vec F_2 and \vec F_3:

\vec F_2\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_2\cdot\vec F_4=-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)

\vec F_3\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies\vec F_3\cdot\vec F_4=-{F_3}^2

Finally, if we do this with \vec F_4, we get

\vec F_4\cdot(\vec F_1+\vec F_2+\vec F_3+\vec F_4)=0

\implies{F_4}^2=-\left(\vec F_1\cdot\vec F_4+\vec F_2\cdot\vec F_4+\vec F_3\cdot\vec F_4\right)

\implies{F_4}^2=-\left(-\left({F_1}^2+\vec F_1\cdot\vec F_2\right)-\left(\vec F_1\cdot\vec F_2+{F_2}^2\right)-{F_3}^2\right)

\implies F_4=\sqrt{{F_1}^2+{F_2}^2+{F_3}^2+2(\vec F_1\cdot\vec F_2)}

\implies\boxed{F_4\approx36.2\,\mathrm N}

7 0
3 years ago
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