Answer:
The answer is B.
Step-by-step explanation:
12 ≤ r + 22
r + 22 ≥ 12
r + 22 − 22 ≥ 12 − 22
r ≥ −10
I hope this helps you :D
P(2 or 4) = 2/3
p(multiple of 2) = 1
p(multiple of 3) = 1/3
P(odd prime numbers) = 0
<h3>What are the probabilities?</h3>
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
P(2 or 4) = (number of sides that have a value of 2 / total number of sides) + (number of sides that have a value of 2 / total number of sides) = 2/6 + 2/6 = 2/3
p(multiple of 2) = number of sides that are a multiple of 2 / total number of sides
6/6 = 1
p(multiple of 3) = number of sides that are a multiple of 3/ total number of sides
= 2/6 = 1/3
P(odd prime numbers) = number of odd prime numbers / total number of sides = 0
To learn more about probability, please check: brainly.com/question/13234031
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Well the domain is the x value and how much far it goes same with the range it is just the y value :)
So..to make it easier you can jut multiply by 2 on both sides...
so you get 3y-2y=8+y..
which is equal to 0=8..but because they arent equal it means that there is no solution.
Answer:
For 36 movies the cost of both the plans is same.
Step-by-step explanation:
Let us assume foe m movies, both the plans cost same.
Now, PLAN A:
Annual Fee = $45
Cost per movie = $2.50
⇒The cost of watching m movies = m x (Cost of 1 movie)
= m x ($2.50) = 2.5 m
So, the total cost of Plan A = Annual Fee + Cost of m moves
= 45 + 2.50 m
PLAN B:
Cost per movie = $3.75
⇒The cost of watching m movies = m x (Cost of 1 movie)
= m x ($3.75) = 3.75 m
ACCORDING TO QUESTION:
for m movies, Cost of plan A = Cost of plan B
⇒45 + 2.50 m = 3.75 m
or, 3.75 m - 2.5 m = 45
or, m = 45/1.25 = 36
or, m = 36
Hence, for 36 movies the cost of both the plans is same.
