Answer:
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.print("Input a word: ");
String userinput = input.nextLine();
for(int i =0;i<userinput.length();i+=2) {
System.out.print(userinput.charAt(i));
}
}
}
Explanation:
This line prompts user for input
System.out.print("Input a word: ");
This declares a string variable named userinput and also gets input from the user
String userinput = input.nextLine();
The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2
for(int i =0;i<userinput.length();i+=2) {
This prints characters at i-th position
System.out.print(userinput.charAt(i));
Answer:
this isn't a fair question...
you'll either get 2,3 or 4
not a nice question
Answer:
b) void xyzfunc (int &myint);
Explanation:
To use the same memory location as the variable in the calling function we have to pass the variable by reference means passing the same address to the function.So to do that we have use & operator which stands for address.
We will do this as following:-
void xyzfunc (int * myint);
Hence the answer is option b.