Answer: The difference between call by value and call by reference is that in call by value the actual parameters are passed into the function as arguments whereas in call by reference the address of the variables are sent as parameters.
Explanation:
Some examples are:
call by value
#include <stdio.h>
void swap(int, int);
int main()
{ int a = 10, b= 20;
swap(a, b);
printf("a: %d, b: %d\n", a, b);
}
void swap(int c, int d)
{
int t;
t = c; c = d; d = t;
}
OUTPUT
a: 10, b: 20
The value of a and b remain unchanged as the values are local
//call by reference
#include <stdio.h>
void swap(int*, int*);
int main()
{
int a = 10, b = 20;
swap(&a, &b); //passing the address
printf("a: %d, b: %d\n", a, b);
}
void swap(int *c, int *d)
{
int t;
t = *c; *c = *d; *d = t;
}
OUTPUT
a: 20, b: 10
due to dereferencing by the pointer the value can be changed which is call by reference
Answer:
You forgot to add a group of choices, however assuming this programming language uses 0-based indexes the answer would be x - 1
Explanation:
Zero based index languages have array indexes starting at 0. When you create that array, you use x to define the amount of elements, however due to the array starting at the index 0, the arrays highest index would be x - 1 instead of x.
You have to think about, what could happen to you if you shared this information.
Hope this helped!
~Izzy
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