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nika2105 [10]
3 years ago
8

Jenna’s method: Mia’s method: 5(30 4) 5(30 4) (5)(30) (5)(4) 5(34) = 170 150 20 = 170 Explain why both Jenna and Mia arrived at

the same answer and the advantage of one method over the other.
SAT
1 answer:
Alja [10]3 years ago
3 0

Answer:

HAHAHHHAHHAHAAH

Explanation:

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A coin is tossed 5 times what is the probability of getting all heads? Express your answer as a simplified fraction or a decimal
Evgen [1.6K]

Answer:

1/32 or 0.0313

Explanation:

chance of 1 head = 1/2

all heads => \frac{1}{2} ^{5}  = \frac{1}{32}

7 0
3 years ago
A 40-kilogram mass is moving across a horizontal surface at 5.0 m/s. what is the magnitude of the net force required to bring th
aliina [53]

Answer:

25 N

Explanation:

Use the equation F = m(Vf–Vi) / Δt.

average force = mass (final velocity - initial velocity) / change in time

F = 40 kg(5.0 m/s) / 8.0 s = 200 / 8.0 = 25 kgm / s^2 = 25 Newtons

4 0
3 years ago
Choose THREE agricultural activities that humans perform to minimize their impact on climate change.
Levart [38]

Answer:

B,C and E are the three agricultural activities that humans perform to minimize their impact on climate change.

7 0
2 years ago
Two 99 percent confidence intervals will be constructed to estimate the difference in means of two populations, r and w. One con
Phoenix [80]

The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉

<h3>How to calculate width of the confidence interval with normal distribution?</h3>

The width of the confidence interval will be calculated from the formula;

W = 2Z(σ/√n)

where;

z is the z-score at given confidence level

σ is standard deviation

n is sample size

For first sample;

W_i9 = 2Z(σ/√9)

W_i9 =  ²/₃Zσ

For second Sample;

W_i81 = 2Z(σ/√81)

W_i81 = ²/₉Zσ

Thus, we will have;

W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)

W_i9/W_i81 = 9

W_i81 = ¹/₉W_i9

Read more about width of confidence interval at; brainly.com/question/15934877

6 0
3 years ago
A pendulum is made by tying a 75 g ball to a 130-cm-long string. the ball is pulled 5.0∘ to the side and released.
Maslowich

The ball’s speed and direction at the lowest point of trajectory are; 3.1 m/s and swing to the same angle on the other side

<h3>What is the speed at the lowest point?</h3>

We will assume that all of the motion will transfer to Kinetic Energy at the lowest point. Now, the difference in height will be;

Δh = (130 – 130*cos °5) = 0.49 cm

The change in PE is;

ΔP.E = mgΔh

ΔP.E = 9.8m/s² × 0.75kg × 0.049 m

ΔP.E = 0.36015 J

Formula for kinetic energy is;

K.E = ¹/₂*m*v²

From conservation of energy;

K.E = P.E

Thus;

¹/₂* 0.075 * v² = 0.36015

v = √[(0.36015 * 2)/0.075]

v = 3.1 m/s

Thus, the pendulum will swing to the same angle on the other side.

Read more about Speed of Pendulum at; brainly.com/question/17054952

6 0
2 years ago
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