<u>Answer:</u>
first multiply 3 with −8 and we get − 24
then find two numbers that if we add or subtract we get + 10 and if we multiply we get − 24
and the numbers are + 12 and −2
then we place those numbers as follow :-
3x²+12x−2x−8
then we group them
(3x2+12x)(−2x−8)
now take the common factor out.
3x(x+4)−2(x+4)
then group the numbers outside of the brackets
(3x−2)(x+4)
<em><u>And that is the answer</u></em><em><u>:</u></em>
<em>Proper Solution:-</em>
<em>1.) <u>3x2+10x−8</u></em>
<em>2.) <u>3x2+12x−2x−8</u></em>
<em>3.) <u>(3x2+12x)(−2x−8)</u></em>
<em>4.) <u>3x(x+4)−2(x+4)</u></em>
<em>5.) <u>(3x−2)(x+4)</u></em>