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Arlecino [84]
3 years ago
7

Help please --- multiplying rational numbers

Mathematics
2 answers:
Greeley [361]3 years ago
8 0

Answer:

B

Step-by-step explanation:

0.5 is half so 65 divided by 2 = 32.5

Ugo [173]3 years ago
7 0

Answer:

Im sorry i dont understand

Step-by-step explanation:

I

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Cuanto es 5 kilos en libras ?
Volgvan

Answer:

11.02

Step-by-step explanation:

6 0
3 years ago
Ed bus a box of eggs costing £2.30, two packs of bacon for £2.60 each and two tins of baked beans. He pays with a £10 note gets
kirill115 [55]

Answer:

£0.85 for each

£1.70 for both

Step-by-step explanation:

Variable x = cost of baked beans

2.30 + 2(2.60) + 2x = 10 - 0.80

Use PEMDAS

2.30 + 5.20 + 2x = 10 - 0.80

7.50 + 2x = 9.20

Subtract both sides by 7.50

2x = 1.70

Divide both sides by 2 to isolate the variable

x = 0.85

Let's check our work by plugging this into our original equation

2.30 + 2(2.60) + 2(0.85) = 10 - 0.80

2.30 + 5.20 + 1.70 = 10 - 0.80

7.50 + 1.70 = 9.20

9.20 = 9.20

Our number is correct

7 0
3 years ago
okay keep scrolling if you are doing school......please help...... how many of yall single? because I haven't been single for a
saw5 [17]

Answer:

how old r u

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
What is the equation of the line that passes through (5,-2) and (-3, 4)?
natali 33 [55]
3x-4y-7= 0 is the answer
8 0
3 years ago
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