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Reil [10]
3 years ago
6

Melissa graphed the equation y = x2 and Dave

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

Dave's graph has been reflectes across the x-axis and has a horizontal stretch compared to Melissa's graph.

Step-by-step explanation:

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3 years ago
HELP WITH THESE QUESTIONS PART 2... 1 Question
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(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}}) is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = \sqrt{10}

sin = \frac{opposite}{hypotenuse} = \frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{3\sqrt{10}}{10}

cos =  \frac{adjacent}{hypotenuse} = \frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}}) = \frac{\sqrt{10}}{10}

tan = \frac{opposite}{adjacent} = \frac{3}{1} = 3

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cot = \frac{adjacent}{opposite} = \frac{1}{3}

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