3/10 because 2/5 is also equal to 4/10 so therefore 3/10 is smaller than 4/10
Answer:26
Step-by-step explanation:
85*2=170
170+64+x=360
234+x=360
x=126
The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;
- Width ≈ 8.89 in., length ≈ 24.89 in., height ≈ 4.55 in.
- Maximum volume of the box is approximately 1048.6 in.³
<h3>How can the dimensions and volume of the box be calculated?</h3>
The given dimensions of the cardboard are;
Width = 18 inches
Length = 35 inches
Let <em>x </em>represent the side lengths of the cut squares, we have;
Width of the box formed = 18 - 2•x
Length of the box = 35 - 2•x
Height of the box = x
Volume, <em>V</em>, of the box is therefore;
V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x
By differentiation, at the extreme locations, we have;

Which gives;

6•x² - 106•x + 315 = 0

Therefore;
x ≈ 4.55, or x ≈ -5.55
When x ≈ 4.55, we have;
V = 4•x³ - 106•x² + 630•x
Which gives;
V ≈ 1048.6
When x ≈ -5.55, we have;
V ≈ -7450.8
The dimensions of the box that gives the maximum volume are therefore;
- Width ≈ 18 - 2×4.55 in. = 8.89 in.
- Length of the box ≈ 35 - 2×4.55 in. = 24.89 in.
- The maximum volume of the box, <em>V </em><em> </em>≈ 1048.6 in.³
Learn more about differentiation and integration here:
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Answer:
7 cm
Step-by-step explanation:
it is a square so sqrt(49)=7, and the side lengths are 7
Answer:
50⁰
Step-by-step explanation:
Since j and k are parallel lines cut by two transversals,
2+3+5=180⁰ <em>(</em><em>Allied</em><em> </em><em>angles</em><em>)</em>
We are given 2(60⁰) and 5(70⁰)
so,
60⁰+3+70⁰=180⁰
60+70=130
130⁰+3=180⁰
Bring the 130⁰ to the R.H.S
3=180⁰-130⁰
Therefore,
3=50⁰