Bc. log a - log b = log (a/b) than use this formula will get
log x^2 -log x = log (x^2 /x) = log x so choice D. is right sure
hope helped
A. 1/5k - 2/3j and -2/3j + 1/5k
Step-by-step explanation:
Equivalent expressions are expressions that are the same even though they may appear different.When you plug in a value to represent a variable in these expression, they will give same answer when simplified.
In
1/5k - 2/3j and -2/3j + 1/5k you notice the operation signs in the terms has been maintained though the position of the terms shifted.
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Answer:
Converges at -1
Step-by-step explanation:
The integral converges if the limit exists, if the limit does not exist or if the limit is infinity it diverges.
We will make use of integral by parts to determine:
let:





We can therefore determine that if x tends to 0 the limit is -1

Answer:
(-5,-3.5) is the midpoint
Step-by-step explanation:
See photo for the step-by-step explanation
To find the least common denominator, or lcd, you have to find the least common multiple, or lcm. To do that you find the multiples of each number until they equal each other. I set up a chart like this,
6 -
8 -
and then I start listing multiples so,
6 - 6, 12, 18, 24,
8 - 8, 16, 24,
I stop after I find a number they are both equal to. So to get to that number I would multiply 8 by 3, and 6 by 4. This gives me 24 as the lcd. If you need the lcd to add the fractions together, then whatever you did to the bottom do to the top. So 5/6 would become 20/24 and 3/8 would become 9/24.
Answer: 24