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Nataliya [291]
3 years ago
6

Representation of the function f(x)=-2x2+8x-6

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0
X-intercepts: (1,0), (3,0)
Y-intercepts: (-6,0)
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6. A prism has bases that are equilateral triangles with sides lengths of 10 inches and a length of 30 inches.
eimsori [14]

Answer:

The volume of the prism is 1,299\ in^{3}

Step-by-step explanation:

we know that

The volume of the prism is equal to

V=BL

where

B is the area of the triangular base

L is the length of the prism

we have

L=30\ in

<em>Find the area of the base B</em>

The area of a equilateral triangle is equal to

B=\frac{1}{2}(10)^{2} sin(60\°)

B=25\sqrt{3}\ in^{2}

substitute

V=(25\sqrt{3})(30)=1,299\ in^{3}

8 0
3 years ago
*****urgent help ****Write 2447457.627 in standard form to a appropriate degree of accuracy pls i need help
erica [24]

Answer:

2.447457627 x 10^6

Step-by-step explanation:

If this helped can i have Brainliest

5 0
3 years ago
to the nearest ten thousand, the population of Vermont was estimated to be about 620,000 in 2008.What might have been the exact
sp2606 [1]
There Are Multiple Answers.... Here are 5 possible answers

•616,825
•618,471
•617,071
•619,664
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6 0
3 years ago
P(x)=-4x-2<br> Find p(a-3)
Marta_Voda [28]
Answer : -4a+10

Substitute (a-3) for x
-4(a-3)-2
-4a+12-2
-4a+10 but can also be written as -2(2a-5)
7 0
3 years ago
Find the exact value of sin2 theta given sin theta =5/13, 90°&lt;theta &lt;180°
Zepler [3.9K]
Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}&#10;\\\\\\&#10;\textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}

\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}&#10;\\\\\\&#10;therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}&#10;\\\\&#10;-------------------------------\\\\&#10;sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13}  \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}
3 0
4 years ago
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