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2 years ago

. 5.8x10 to the power of 7

Mathematics

1 answer:

Delvig [45]2 years ago

4 0

PEMDAS means we do exponents before we multiply.

10 ^ 7 = 10,000,000

(10 * 10 * 10 * 10 * 10 * 10 * 10)

5.8 * 10,000,000

= 58,000,000

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What is the equation of the translated function, g(x), if

Ivanshal [37]

Answer:

D. g(x) = (x+ 4)² + 6

Step-by-step explanation:

Here, the given function is f(x) = x²

Now,if a graph x² is translated by (h,k) where:

h = Translation done towards RIGHT

k = Translation done towards UP

Then the translated equation is given as:

y = (x-h)² + k .... (1)

Now here, the graph is translated 6 UNITS UP and 4 UNITS LEFT.

⇒ h = - 4 and k = 6

Substituting the value of h, k in (1) , we get:

g(x) = (x-(-4))² + 6 = (x+ 4)² + 6

⇒ g(x) = (x+ 4)² + 6

Hence, the equation of the translated function, g(x) is g(x) = (x+ 4)² + 6.

3 0

2 years ago

Determine the product, h (x), of the linear and quadratic factors.

Wewaii [24]

$h(x) =8x^3-19x^2+14x-3$

Step-by-step explanation:

Given functions are:

$f(x) = 8x-3\\g(x) = (x-1)^2$

h(x) is the product of g(x) and f(x)

$h(x) = f(x) * g(x)\\= (8x-3)(x-1)^2\\= (8x-3)(x^2-2x+1)\\= 8x(x^2-2x+1)-3(x^2-2x+1)\\= 8x^3-16x^2+8x-3x^2+6x-3$

Combining like terms

$=8x^3-16x^2-3x^2+8x+6x-3\\=8x^3-19x^2+14x-3$

Hence,

$h(x) =8x^3-19x^2+14x-3$

Keywords: Functions, product

Learn more about functions at:

#LearnwithBrainly

8 0

3 years ago

Please help a14= 1 2 5

Butoxors [25]

ANSWER

$a_{14} = 5$

EXPLANATION

The given matrix is a 4 by 4 matrix.

We want to find

$a_{14}$

This is the entry in Row 1 Column 4.

We trace row 1 Column 4 and identify the entry in their intersection.

This entry is 5

$a_{14} = 5$

3 0

3 years ago

the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region

m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

$\frac{x}{360} \pi {r}^{2}$

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

$16 = \sqrt{10 {}^{2} + 10 {}^{2} - 2(100) \times \cos(o) }$

This isn't the standard formula, it's for this problem

$16 = \sqrt{200 - 200 \times \cos(o) }$

$16 = \sqrt{200 - 200 \cos(o) }$

$256 = 200 - 200 \cos(o)$

$56 = - 200 \cos(o)$

$- \frac{7}{25} = \cos(o)$

$\cos {}^{ - 1} ( - \frac{7}{25} ) = \cos {}^{ - 1} ( \cos(o) )$

$106.26 = o$

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

$\frac{106.26}{360} (100)\pi$

$\frac{10626}{360} \pi$

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

$\frac{36}{2} = 18$

$\sqrt{18(18 - 10)(18 - 10)(18 - 16)}$

$\sqrt{18(8)(8)(2)}$

$\sqrt{(36)(64)}$

$6 \times 8 = 48$

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

$\frac{10626}{360} - 48$

Which is an approximate or

44.73

6 0

2 years ago

Help me with this question please I’m lost

Damm [24]

Answer:

1.03*10(-25)

Step-by-step explanation:

3 0

3 years ago

. 5.8x10 to the power of 7​

. 5.8x10 to the power of 7