Question

Write the equation of a line with slope of 5/6 , and x-intercept of −8 in point-slope form.

Answer 1

Answer:  $y-0 = \frac{5}{6}(x+8)$

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Explanation:

Point-slope form is

$y - y_1 = m(x - x_1)$

where m is the slope and $(x_1,y_1)$ is the point the line goes through.

We're given the slope of m = 5/6, and we want the line going through (-8,0) which is the x-intercept -8. The x-intercept always occurs when y = 0.

So,

$y - y_1 = m(x - x_1)\\\\y - 0 = \frac{5}{6}(x - (-8))\\\\y - 0 = \frac{5}{6}(x + 8)$

We can replace the y-0 with y; however, I'm going to keep that 0 so that the equation better matches the point-slope form.