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padilas [110]
3 years ago
5

Whats 23.95 x 17.3? Please let me know below

Mathematics
2 answers:
BARSIC [14]3 years ago
7 0

Answer:

414.335

Step-by-step explanation:

Put the 23.95 on top of the 17.3

Ira Lisetskai [31]3 years ago
3 0
414.335 because of a calculator
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A bill for Rs 3235 was drawn on Feb. 3, 1998 at 6 months and discounted on March 3, 1998 at 8 % p.a. Find the value of the bill
Fantom [35]

Answer:

RS 3127.166

RS 107.834

Step-by-step explanation:

6 month bill :

Drawn date = Feb, 3

Discounted date = March 3,

Difference = 1 month

6 month - 1 month = 5 months = 5 * 30 = 150 days

Value of the bill :

P(1 - rate * time)

3235(1 - 0.08 * 150/360)

3235(1 - 0.08 * 0.4166666)

3235(1 - 0.0333333)

3235(0.9666666)

= Rs3127.1666

Value of bill = 3127.166

Bankers gain = 3235 - 3127.166 = 107.834

6 0
3 years ago
PLEASE HELP ASAP MARKING BRAINLEIST + 50 POINTS
Lorico [155]

Answer:

scale factor = \frac{1}{5}

Step-by-step explanation:

the scale factor is the ratio of corresponding sides, image to original, so

scale factor = \frac{V'W'}{VW} = \frac{1}{5}

3 0
2 years ago
The base of a solid is the region in the first quadrant bounded by the line x=-2y+6 and the coordinate axes. What is the volume
nika2105 [10]

Answer:

V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3

V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36

Step-by-step explanation:

For this case we have the following plot on the figure attached.

We know on this case that x = -2y+6 represent our radius for the square, since we need cross sections perpendicular to the y axis.

We find the intersection points like this:

x= 0 , y=3

y=0, x=6

Since we are assuming squares for the cross sections the area is given by A = r^2 where r = x= -2y+6.

Since our radius is on terms of x we can create a integral with limits on x in order to find the volume, And we can use the following integral in order to find the volume.

V = \int_{0}^3 (-2y+6)^2 = \int_{0}^3 4y^2 -24y +36 dy

On the left part we are using the following property from algebra:

(a+b)^2 = a^2 +2ab +b^2

(-2y+6)^2 = (-2y)^2 +2*(-2y)(6) +(6)^2 = 4y^2 -24y+36

And after do the integral we got this:

V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3

V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36

7 0
3 years ago
What is the nth term rule of the linear<br> sequence<br> below?<br> 1, 7, 13, 19, 25, . ..
vampirchik [111]

Answer:

Un= 1+(n-1)6

Step-by-step explanation:

a = 1

d= 7-1= 13-7= 6

and using the formula, Un= a+(n-1)d

5 0
2 years ago
I will givee Brainlist if anyone answers all these questions
vaieri [72.5K]
Theirs no picture, I dong know if you forgot to put it along with it but theirs nothing to answer
5 0
3 years ago
Read 2 more answers
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