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Nat2105 [25]
3 years ago
10

I will givee Brainlist if anyone answers all these questions

Mathematics
2 answers:
vaieri [72.5K]3 years ago
5 0
Theirs no picture, I dong know if you forgot to put it along with it but theirs nothing to answer
Troyanec [42]3 years ago
5 0

Answer:

There i no questions to answer on here

Step-by-step explanation:

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Which term of ap 30,27,24is0
son4ous [18]

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

8 0
3 years ago
A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write
Alenkinab [10]
The line passes through two points that have the same x-coordinate.
It is a vertical line. To find the slope of a line, use any two points. Subtract the y-coordinates. Subtract the x-coordinates in the same order. Then divide the difference of the y-coordinates by the difference of the x-coordinates. Since in this case, the x-coordinates are both -6, the difference between the x-coordinates is zero. Division by zero is not defined, so the slope of this line is undefined. You can't write its equation in point-slope form, because there is no slope for this line.
3 0
3 years ago
Can you find the mean for these two questions:
Molodets [167]

1) Mean Absolute Deviation = 1.75


2) Mean = 244

7 0
4 years ago
Read 2 more answers
48 = 4t + 12<br> How would I solve this someone please respond fast.
raketka [301]

Answer:

t=9

Step-by-step explanation:

Move all terms that don't contain

t to the right side and solve.t=9

8 0
3 years ago
Read 2 more answers
What is the value of b ?
HACTEHA [7]

Two polynomials are equal if the coefficients are equal.

x^3+(3+b)x^2+(3b-2)x-6\\\downarrow\qquad\ \ \downarrow\qquad\qquad\ \ \ \ \downarrow\\x^3\ +\ \ 6x^2\ \ \ \ +\ \ \ \ \ 7x\ \ -\ 6\\\\x^3\to1=1\\x^2\to3+b=6\\x\to3b-2=7\\constans\to-6=-6\\\\3+b=6\ \wedge\ 3b-2=7\\\\3+b=6\ \ \ |-3\\b=3\\\\3b-2=\ \ \ \ |+2\\3b=9\ \ \ \ |:3\\b=3\\\\Answer:\ \boxed{b=3}\to\boxed{B.}

6 0
3 years ago
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