Ask question

Ask question

All categories

LUCKY_DIMON [66]

3 years ago

7

Can someone help me, please?

1 answer:

Anika [276]3 years ago

3 0

The value of AE is 112 thanks to the Triangle Midsegment Theorem. Hope this helps!

You might be interested in

How do I solve this problem because I don’t understand

Citrus2011 [14]

You are using a^2+b^2=c^2
since c is the hypotenuse

#1 the equation would be 16^2+b^2=34^2
16^2= 256
34^2= 1156
1156-256= 900
b^2=900 (now find square root of 900)
b= 30

You are now trying to find the hypotenuse or c in this so it is simpler

#2 equation - 4^2+2^2=c^2
16+4=c^2
20=c^2
c= 4.27

4 0

3 years ago

What is √25 times√81 times 0?

GrogVix [38]

Well, when any equation has a 0 multiplied into it, the answer will be zero.
Anyway, √25 equals 5
√81 equals 9
9*5 = 45
45 * 0 = 0
I hoped I helped!

6 0

3 years ago

Help help help helpppp ASAP!

Margarita [4]

Answer: 12n-10= -58

+10. +10 (add to both sides)

12n. = -48

÷12. ÷12 (isolate variable)

n. = -4

6 0

3 years ago

Read 2 more answers

3) A tour trolley covers a distance of 8.5 miles in of an hour.

sp2606 [1]

Answer:

a) Ans: 8.5 miles per hour

b) Ans: 46.75 miles

Step-by-step explanation:

a) Speed = Distance/Time

8.5/1h = 8.5 miles per hour

b) Distance = Speed x Time

8.5 miles per hour x 5.5h = 46.75 miles

5 0

3 years ago

Determine the function which corresponds to the given graph. (3 points) a natural logarithmic function crossing the x axis at ne

quester [9]

Answer:

$y =log_e(x+3)$

Step-by-step explanation:

It is given that the graph corresponds to a natural logarithmic function.

That means, the function $y$ has a natural log (Log with base $e$ ) of some terms of x.

It is given that asymptote of given curve is at $x= -3$ . i.e. when we put value

$x= -3$ , the function will have a value $y \rightarrow \infty$ .

We know that natural log of 0 is not defined.

So, we can say the following:

$log_e(x+a)$ is not defined at $x= -3$

$\Rightarrow x+a =0\\\Rightarrow x = -a$

i.e. $x =-a$ is the point where $y \rightarrow \infty$

a = 3

Hence, the function becomes:

$y =log_e(x+3)$

Also, given that the graph crosses x axis at x = -2

When we put x = -2 in the function:

$y =log_e(-2+3) = log_e(1) = 0$

And y axis at 1.

Put x = 0, we should get y = 1

$y =log_e(0+3) = log_e(3) \approx 1$

So, the function is: $y =log_e(x+3)$

4 0

4 years ago