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frez [133]
3 years ago
10

Find the tenth term in the pattern

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0

9514 1404 393

Answer:

  1000

Step-by-step explanation:

The pattern is the sequence of cubes. The 10th cube is ...

  10³ = 10·10·10 = 1000 . . . . 10th term of the pattern

_____

<em>Additional comment</em>

It is helpful to memorize the squares of integers 1-20 and the cubes of integers 1-10. Being able to recognize these numbers can save you a lot of time on problems like this.

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The sum of five more than a certain number and 10 more than twice the number is equal to the product of 2 and the number increas
d1i1m1o1n [39]

Answer:

No solution

Step-by-step explanation:

10+2x=2x+8

2x=2x-2

0≠-2

7 0
3 years ago
Show that 64 can be written as either 2^6 or 4^3​
lord [1]

Answer:

Step-by-step explanation:

2^6 because

2 times 2 times 2 times 2 times 2 times 2 is 64

2 times 2 is 4 times 2 is 8 times 2 is 16 times 2 is 32 times 2 is 64

8 0
3 years ago
A group of 3 explorers travelled through the new Guinea rain forests with 3 Marind-Anim guides. Their inflatable dinghy could on
Lesechka [4]

Answer:

Hello,

Step-by-step explanation:

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Only A and X can operate the boat.

\begin{array}{|c|c|c|}border\ 1 &boat&border\ 2\\ABCXYZ&-&-\\BCYZ&AX&-\\BCYZ&A&X\\BCY&AZ&X\\BCY&A&XZ\\CY&AB&XZ\\CY&X&ABZ\\Y&CX&ABZ\\Y&X&ABCZ\\-&XY&ABCZ\\-&-&ABCXYZ\\\end{array}

I hope you will understand the travels

4 0
2 years ago
Find the interquartile range. its question 5 and four
sergeinik [125]

Answer:

I think the interquartile range is 2.5

Step-by-step explanation:

Interquartile range = Q3-Q1.

7 0
3 years ago
The histogram to the right represents the weights​ (in pounds) of members of a certain​ high-school debate team. What is the cla
nikitadnepr [17]

Answer:

Class width = 20

Approximate lower class limit of the first class = 110

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Step-by-step Explanation:

The class width of the histogram attached below can be gotten by finding the difference between successive lower class limits.

Thus, class width = 130 - 110 = 20

The approximate lower class limit of the first class is the lowest score we have in the first class = 110

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8 0
4 years ago
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