Ask question

Ask question

All categories

denis-greek [22]

4 years ago

7

The average of three numbers is 22. the average of two numbers is also 22. what is the value of the third number in the original

3?
A.20 B.21 C.22 D.23 E.24

2 answers:

IRINA_888 [86]4 years ago

8 0

Answer:

C

Step-by-step explanation:

If the average wasn't shifted at all, that means the third value must've been the same as the average to not shift it.

AnnZ [28]4 years ago

6 0

The answer I think is correct is C.22

You might be interested in

-3q + 12 greater than equal too 4q - 30 solve for q

valentina_108 [34]

Solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Step-by-step explanation:

We need to solve the inequality: $-3q+12\geq 4q-30$ and find value of q

Solving:

$-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6$

So, solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Keywords: Solving inequality

Learn more about solving inequality at:

#learnwithBrainly

6 0

3 years ago

1m as a percentage of 56mm

andreev551 [17]

Answer:

1785.71429% or ~1785.71%

Step-by-step explanation:

to find this answer you must divide 56 mm by 1 m

1 m is also 1000 mm

so

1000 / 56 is what you need to do

1000/56 = 17.8571429

your percentage is essentially 1785.71429%

8 0

2 years ago

Read 2 more answers

Can u plzz find me a length of adjacent

timofeeve [1]

Answer:

There is no answer

My Logic:

The picture does not specify the degree of angle for each corner, nor can i understand what the random "a" is. also the side all the way to the left has an un-readable number.

6 0

3 years ago

The sum of 423 and 65 is

Akimi4 [234]

Answer:

488

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A child types the letters q, w, e, r, t, y, randomly producing 1000 letters in all. what is the expected number of times that th

notka56 [123]

1/6*1/6*1/6*1/6 = 1/1296 = 0.078% probability of ANY 4-letter sequence (including qqqq)
1000/1296 is less than 1.
Expected number of times qqqq (or any given 4-letter sequence) will appear in 1000 letters is 0.

7 0

3 years ago