Answer:
-71i + 12j +47k
Step-by-step explanation:
The notation of the distance moved
In x-direction = -71
Considering the left side as the positive y- direction;
In y-direction= 12
In z-direction = 47
Therefore, the vector notation is
Displacement r = -71i + 12j + 47k
Answer:
The answer to your question is given below.
Step-by-step explanation:
Let the total number be U.
From the question given above, we were told that any number of B is 50% of the total number (i.e U).
Now, we shall determine the the total number (U) in terms of B.
50% of U = B
50/100 × U = B
50U / 100 = B
Cross multiply
50U = 100B
Divide both side by 50
U = 100B/50
U = 2B
Thus, the total number is 2B
Finally, we shall determine the answer to the question:
111 is 50% of ___
B = 111
Total number (U) = 2B
Total number (U) = 2 × 111
Total number (U) = 222
Therefore,
111 is 50% of 222
On the first day, they traveled for 10 hours with an average speed of 60 mph. Which means on the first day they traveled 600 miles.
Since the total distance is 1023 miles and presumably they will be going at a speed of 60 mph. We divide the miles by the rate:
1023/60 = 17.05
So it will take 17.05 hours to drive the whole way to Florida.
I think it’s 3/2 .. cause the lines are plotted on 3 and 2
Answer:
In many cases, the function is easily evaluated and/or graphed for those x-values.
Step-by-step explanation:
We are usually interested in x-values that relate to the problem at hand. In many cases, the functions we study are graphed on a coordinate plane that includes the origin and a few numbers in every direction. That is, x-values of -2, -1, 0, 1, 2 are right in the middle of the graph we want to create.
Another reason for choosing small values of x is that we may want to raise these values to some power (as for evaluating a polynomial). Many of us have memorized the first few powers of the first few integers, so using small integers makes the evaluation easier.
___
That is not always the case. Some functions may not be defined for negative values of x, or those values may not exist in the "practical domain" of the function. Trigonometric functions may be more easily evaluated for multiples of π/6, instead of small integers. Other functions may be scaled or offset so that small integer values of x are of no interest.
