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DIA [1.3K]
2 years ago
8

Help please i’m begging

Mathematics
1 answer:
fomenos2 years ago
3 0

Answer:

Y=-128

Step-by-step explanation:

Y=-200-6(-12)

Y=-200+72

+200

200+y=72

-200

Y=-128

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Elizabeth bought 6 lipsticks for $15. How many lipsticks can be bought for $60
dmitriy555 [2]

Answer:

4 lipsticks

Step-by-step explanation:

15+15=30, 30+30=60

3 0
2 years ago
Three-fifths of a number increased by ten
Sav [38]

Answer: \frac{3}{5} x+10

Step-by-step explanation:

three-fifths of a number means multiply three-fifths by a variable \frac{3}{5} x

increased by 10 means addition +10

together it is \frac{3}{5}x +10

4 0
3 years ago
2. Find the missing angle x.<br> 155°<br> 60°<br> X
Kryger [21]

Answer:

exterior angle property use ...

the exterior angle of an angle is equal to sum of rest 2 interior angles in a triangle

155 = 60 + x

x = 155 - 60 = 95

8 0
3 years ago
Can i please get help with these
Kryger [21]

Answer:

7. x=3, 8. x=7, 9. x=15.

Step-by-step explanation:

7. If lines m and n are congruent, then angles DCF and CFE are congruent. 15x+3=18x-6. Solve for x. --> 15x+9=18x-->3x=9-->x=3

8.If line m is parallel to line n, then the corresponding angles are congruent. So, 20x+1=22x-13 Solve for x. 20x+14=22x-->14=2x-->x=7.

9. The supplementary angle of 110 is 70. Note that all of the inner angles of a triangle are equal to 180. Form an equation using the the values: (4x+8)+(2x+12)+70=180. Simplify; 6x+90=180. Solve for x: 6x+90=180-->6x=90-->x=15.

Hope this helps!

8 0
2 years ago
A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have thr
kati45 [8]

Answer:

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

23\cdot 23\cdot 23\cdot 6\cdot 6=438012

Therefore, we can choose coupon codes in 438,012 ways.

3 0
3 years ago
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