Duruvdidhu you can get my stuff for you today if not I’ll just ask my buddy to come get it
Answer:
50 is correct
Step-by-step explanation:
did my math but I know you need it quick so sorry for brief answer
<span>A) 2x + 4y = 38
B) 10x + 3y = 105
Multiplying A) by -5
A) -10x -20y = -190 then adding it to B)
</span><span>B) 10x + 3y = 105
-17y = -85
y = 5
x = 9
</span>
<u>ANSWER:
</u>
Zach has 28 dimes and 7 quarters.
<u>SOLUTION:
</u>
Given, Zach has 4 times as many dimes as quarters
And they have a combined value of 455 cents,
We need to find how many of each coins does he have?
Let, the number of dimes be x and number of quarters be y.
Then, x = 4y → (1)
Total combined value = 455 cents
x(value of one dime) + y(value of one quarter) = 455 cents
x(10 cents) + x(25 cents) = 455 cents
10x + 25y = 455 → (2)
Now, substitute (1) in (2)
10(4y) + 25y = 455
40x + 25y = 455
65y = 455
y = 7
substitute y value in (1)
x = 4(7) = 28
Hence, zach has 28 dimes and 7 quarters.
