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3 years ago

What is the percentage difference between 50 and 45

Mathematics

1 answer:

Vinil7 [7]3 years ago

6 0

45 is 90 percent of 50. / / / 50 is (111 and 1/9) percent of 45.

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Let the function be f defined by f (x) = 12 - 5x

marissa [1.9K]

(a) No

$f(x) = 12 - 5x$

$f(0) = 12 - 5(0)$

$f(x) = 12 - 0$

$f(x) = 12$

Hence,

f(0) is unequal to 0.

(b)

$f(x) = 12 - 5x$

$f( - 1) = 12 - 5( - 1)$

$f( - 1) = 12 + 5$

$f( - 1) = 17$

(c)

$f(x) = 12 - 5x$

$f(x) = 6$

$6 = 12 - 5x$

$6 - 12 = - 5x$

$- 6 = - 5x$

$6 = 5x$

$\frac{6}{5} = x$

7 0

3 years ago

I have no clue how to solve this please help

borishaifa [10]

What are you trying to solve dear

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3 years ago

a map has a scale of 1.5 inches = 9 miles. On the map, two towns are 4 inches apart. What is the distance, in miles between the

Oksanka [162]

Answer:

Step-by-step explanation:

i multpliy 9x4=36

7 0

3 years ago

Let f(x)=6(2)x−1+4

atroni [7]

G(x)=6(2)x+7+4 i think that is it

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2 years ago

Prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle, the sum of the s

aivan3 [116]

For the answer to the question above asking to prove the Pythagorean Theorem using similar triangles. The Pythagorean Theorem states that in a right triangle,
A right triangle consists of two sides called the legs and one side called the hypotenuse (c²) . The hypotenuse (c²) is the longest side and is opposite the right angle.

⇒ α² + β² = c²

"In any right triangle ( 90° angle) , the sum of the squared lengths of the two legs is equal to the squared length of the hypotenuse."

For example: Find the length of the hypotenuse of a right triangle if the lengths of the other two sides are 3 inches and 4 inches.
c2 = a2+ b2
c2 = 32+ 42
c2 = 9+16
c2 = 15
c = sqrt25
c=5

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3 years ago