Answer:
18. compound interest
19. simple interest
20. simple interest
Step-by-step explanation:
For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...
simple interest multiplier = (1 +rt)
For interest compounded annually, the multiplier of the initial balance is ...
compound interest multiplier = (1 +r)^t
A spreadsheet can do the computations for you.
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As an example of the computations involved, consider problem 19:
simple interest multiplier = 1 + 0.13·6 = 1.78
compound interest multiplier = 1.10^6 = 1.771561
The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.
|4| - |-5|
all the absolute numbers are always positive.
when you will open the brackets positive will remain positive and negative will change to positive so we get
4 - 5
= -1 Ans
Answer:
Sorry I don't remember the answer
X+y = 4, therefore y = 4-x when you rearrange the equation.
You can subsitute this in: x-(4-x) = 6
-4+x = 6-x
x=10-x
2x = 10
x = 5
Substitute x into the previous equation:
5+y = 4
y = 4-5
y = -1
Answer:
The farmer will need 7 crates.
Step-by-step explanation:
<em>It is given that there are 71 pumpkins in total.</em>
<em>And each crate holds 19 pumpkins.</em>
Let the number of crates required be<em> "n".</em>
The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.
Thus, the equation is
![19(n) = 71](https://tex.z-dn.net/?f=19%28n%29%20%3D%2071)
![n = \frac{71}{19} = 7](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B71%7D%7B19%7D%20%3D%207)
Thus, the farmer needs 7 crates to hold total of 71 pumpkins.