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Otrada [13]
3 years ago
13

What is the percentage difference between 50 and 45

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0
45 is 90 percent of 50. / / / 50 is (111 and 1/9) percent of 45.
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Mr. rodriquez was on the telephone for 182 minutes. She called 7 friends to invite them to a luncheon. If she spoke to each frie
vitfil [10]
He spoke to each friends for 26 minutes

How I found out : how I found out is that all you have to do it get the total amount which in this question it is going to be 182. And you would need to dive 182 by 7 to find the unit rate (182/7) which is going to equal 26.which means he called each friend for 26 minutes
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What is the y-intercept of y=5x-1
Sever21 [200]

Answer:

The answer is -1

Step-by-step explanation:

hope it helps

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So what exactly is a,b,c
Gala2k [10]
If you’re talking about answers a would be the option first b would be 2nd and c would be 3rd
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3 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

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3 years ago
A recipe that will make 3 pies calls for 7cups of flour. How many pies can you make with 28 cups of flour?
BaLLatris [955]
You could make 12 pies
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