Alternate exterior angles are the pair of angles that lie on the outer side of the two parallel lines but on either side of the transversal line. Illustration: ... Notice how the pairs of alternating exterior angles lie on opposite sides of the transversal but outside the two parallel lines.
The answers is 59/20 because when you calculate it it say 2.95
The measure of the ∠LQP is 120°
Step-by-step explanation:
The diagram of the question is as attached in the image.
LMNP is a square. We know that for a square all sides are equal and intersects at 90°
Hence, LM=MP=PN=LN
and ∠LMP= ∠MPN= ∠PNL= ∠NLM= 90°
Δ LMQ is an equilateral triangle
We know that for equilateral triangle all sides are equal and all angles are 60°
LM=LQ=QM=MP=PN=LN and
∠LQM= ∠QML= ∠MLQ= 60°
∠LQP= ∠LQM+ ∠MQP eq 1
In Δ MPQ
∠QPM=90° and ∠PMQ= 90°-60°=30°
Hence, ∠MQP= 180°-(90°+30°)=60°
Putting the value of ∠MQP and ∠LQM in equation 1
∠LQP= 60°+60°= 120°
Thus the measure of ∠LQP=120°
Answer:
it is C (4,2) you need to add from 0 to the 5 in yxis then its 4 and in x axis when u go the the right like going up then it is 2 not -2 or whatever
Answer:
Step-by-step explanation:
(-v² - 3v -8)(3v² + 6v + 3) = -v²*(3v² + 6v + 3) -3v*(3v² + 6v + 3) -8*(3v² + 6v + 3)
= -3v⁴ - 6v³ - 3v² -9v³ - 18v² - 9v - 24v² - 48v - 24
{bring the like terms together}
= -3v⁴ - 6v³ - 9v³ -3v² -18v² -24v² - 9v - 48v - 24
= -3v⁴ - 15v³ - 45v² - 57v - 24
HINT:
-v²*(3v² + 6v + 3) = -v²*3v² + (-v²)*6v + (-v²)*3
= -3v²⁺² - 6v²⁺¹ - 3v²
-3v*(3v² + 6v + 3) = -3v*3v² + 6v*(-3v) + 3*(-3v)
= -9v¹⁺² - 18v¹⁺¹ - 9v
= -3v³ - 18v² - 9v
= -3v⁴ - 6v³ - 3v²
