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EastWind [94]
3 years ago
12

Y'=

="\frac{-2x+2y+1}{x-y+1}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

see below

Step-by-step explanation:

 dx        2+2xy         1                1                  2               2

____ =   ______ – ___x^2 – ____y^2 – _____x + ______y

 dy            3            3                3                 3                3

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Use the context of a 24-pack of soda to explain why 3/8 is NOT equivalent to 5/12 . Answer in number of cans.
juin [17]

Answer:

In a 24 pack of soda, 1/8 would be 3 cans (24/8 = 3). 1/12 would be 2 cans (24/12=2).

So 3/8 is 9 cans of soda and 5/12 is 10 cans of soda, so they are not equivalent because the number of soda cans is not the same.

4 0
3 years ago
Find the x and y intercepts for 3x-3y=12
Viktor [21]

\huge \boxed{\sf C}\\\\\\\displaystyle \sf Substituting\ x=0 \\\\3(0)-3y=12\\\\-3y=12\\\\Dividing\ each\ side\ by\ -3 \\\\\frac{-3y}{-3} =\frac{12}{-3} \\\\y=-4 \\\\\\Substituting\ y=0 \\\\3x-3(0)=12\\\\3x=12\\\\Dividing\ each\ side\ by\ 3 \\\\\frac{3x}{3} =\frac{12}{3} \\\\x=4

7 0
1 year ago
What shape are the sides of a rectangular pyramid?
Snowcat [4.5K]

Answer: Its a angle ...

Step-by-step explanation: Hope its fine.

5 0
3 years ago
BRIANLY FOR THE BEST EXPLANATION AND ANSWER!
Kryger [21]

Answer:

C ≈ 14.18

Step-by-step explanation:

<u><em>Question Given:</em></u>

A circle has an area of 16mm². Find it's circumference.

<u><em>Formula:</em></u>

C = 2√πA

<u><em>Solve:</em></u>

C = 2√πA

C = 2√(3.14 × 16)

C = 2√50.24

C = 14.1760361173

C ≈ 14.18

<em>Hence, Circumference is approximately 14.18.</em>

<em />

<u>~Kavinsky</u>

8 0
2 years ago
Read 2 more answers
The half-life of cesium-137 is 30 years. Suppose we have a
VMariaS [17]
(a) If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) e^{kt}=100e^{kt}.

y(30) = 100 e^{30k} = \frac{1}{2}(100) \implies e^{30k} = \frac{1}{2} \implies k = -(\ln 2) /30 \implies \\ \\&#10;y(t) = 100e^{-(\ln 2)t/30} = 100 \cdot 2^{-t/30}

(b) y(100) = 100 \cdot 2^{-100/30} \approx \text{9.92 mg}

(c)
100 e^{- (\ln 2)t/30} = 1\ \implies\ -(\ln 2) t / 30 = \ln \frac{1}{100}\ \implies\ \\ \\&#10;t = -30 \frac{\ln 0.01}{\ln 2} \approx \text{199.3 years}
 
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3 years ago
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