Which fraction equals a repeating decimal 3/10 6/12 1/3 3/4

Solve 4x+5y=13 for y.

inessss [21]

Y = -4x/5 + 13/5 would be the answer to 4x+5y=13

3 0

4 years ago

What is the diameter and radius also the area

adoni [48]

The diameter is 48 feet. The radius is half of the diameter, so it is 24 feet. The area can be found using the formula pi r ^ 2. So, the area is 576 pi

8 0

3 years ago

The price of an item has dropped to $63 today. Yesterday it was $140. What was the percentage decrease?

den301095 [7]

Given:

a.) The price of an item has dropped to $63 today.

b.) Yesterday it was $140.

For us to be able to determine the percentage decrease, we will be using the following formula:

$\text{ Percentage Decrease = }\frac{\text{ Original Price - Present Price}}{\text{ Original Price}}\text{ x 100}$

We get,

Original Price = $140

Present Price = $63

$\text{ Percentage Decrease = }\frac{\text{ Original Price - Present Price}}{\text{ Original Price}}\text{ x 100}$ $\text{ = }\frac{\text{ 140 - 63}}{\text{ 140}}\text{ X 100}$ $\text{ = }\frac{77}{140}\text{ X 100}$ $\text{ = }0.55\text{ x 100}$ $\text{Percentage Decrease = }55\text{\%}$

Therefore, the decrease of the price in percentage is 55%.

4 0

2 years ago

There was a country concert held at the park. For every 3 men there were 5 women that went to the concert. If 30 more women atte

8090 [49]

Answer:

3m == 5w, that means for such unit, there is a 2 person difference

30 person difference = 30/2 = 15units

and again one unit means 3m and 5w

so 15*3men, and 15*5women

and you can check the difference is 30

8 0

3 years ago

When 3010 adults were surveyed in a poll, 27% said that they use the Internet. Is it okay for a newspaper reporter to write th

tamaranim1 [39]

Answer:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

z=2.53

pv=0.0114

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=3010 represent the random sample taken

X represent the people who says that said that they use the Internet.

$\hat p=\frac{X}{106}=0.27$ estimated proportion of people who says that said that they use the Internet.

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.27 -0.25}{\sqrt{\frac{0.25(1-0.25)}{3010}}}=2.53$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

We have the significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.53)=2*(0.0057)=0.0114$

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

3 0

3 years ago