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arlik [135]
2 years ago
14

Please help me if you can. Sorry if it’s blurry

Mathematics
1 answer:
jarptica [38.1K]2 years ago
7 0

Step-by-step explanation:

oh, come on, just multiplication.

7.5×10⁴ years is 7.5×10000 =75000 years.

0.005 inches per year for 75000 years means

0.005 × 75000 = 5 × 75 = 375 inches.

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a storage tank has the dimensions shown below how many storage tanks are needed to contain 60000 cubic meters of liquid
Sladkaya [172]
First find the volume of that container

R = pi (r)^2h
R = pi (15.21)(12.4)
R = 592.5169408

60,000 / R = 101.2629275

102 storage tanks
4 0
3 years ago
What equation is equivalent to the equation 9x - 13 = 4x + 32
Zigmanuir [339]
I’m guessing if you simplify this it’s gonna be x=6
8 0
2 years ago
ABCD is a rectangle and AC and BD are its diagonals. If AC = 10 cm, then BD is?
kiruha [24]

Answer:

A. 10 cm

Step-by-step explanation:

In a right angled triangle, a² + b² = c² where c is the diagonal or hypotenuse. If you split a rectangle diagonally into two right angle triangles, the a and b of both triangles would be the same length. Therefore, the c or diagonals would also be the same length - 10 cm.

Hope this helps!

5 0
2 years ago
Read 2 more answers
Approximate the change in the volume of a sphere when its radius changes from r​ = 40 ft to r equals 40.05 ft (Upper V (r )equal
alexgriva [62]

Answer:

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

Step-by-step explanation:

The volume of the sphere (V), measured in cubic feet, is represented by the following formula:

V = \frac{4\pi}{3}\cdot r^{3}

Where r is the radius of the sphere, measured in feet.

The change in volume is obtained by means of definition of total difference:

\Delta V = \frac{\partial V}{\partial r}\Delta r

The derivative of the volume as a function of radius is:

\frac{\partial V}{\partial r} = 4\pi \cdot r^{2}

Then, the change in volume is expanded:

\Delta V = 4\pi \cdot r^{2}\cdot \Delta r

If r = 40\,ft and \Delta r = 40\,ft-40.05\,ft = 0.05\,ft, the change in the volume of the sphere is approximately:

\Delta V \approx 4\pi\cdot (40\,ft)^{2}\cdot (0.05\,ft)

\Delta V \approx 1005.310\,ft^{3}

The change in the volume of a sphere whose radius changes from 40 feet to 40.05 feet is approximately 1005.310 cubic feet.

7 0
3 years ago
He will look into the matter.<br>change to passive voice​
Veronika [31]

Your question has been heard loud and clear

Passive voice

The matter will be looked into by him.

Thankyou

8 0
3 years ago
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