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sweet-ann [11.9K]
3 years ago
13

Data plays a crucial role in decision-making because it can reveal relationships between different quantities. We often use line

ar equations to model this relationships and make predictions about the data.
Think about a situation when you needed to analyze data. What types of trends did you find in the data? How did noticing the trends help you make a decision related to the situation?
Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0

Answer:

A situation when I needed to analyze data was when I was researching the different prices for ( Input your own thing ) . The type of trend I found in the data was different prices across all websites. I noticed most of the prices are close but some were crazy. I found that the prices resembled a scatter plop. There was a strong ( weak ) positive ( negative ) correlation of 89.667 ( Anything number ). Noticing the trends helped me make a decision related to the situation by allowing me to make the best choice "price-wise" for the NVIDIA GeForce RTX 3090 Graphics card ( enter the same thing you put above ) .

Step-by-step explanation:

Use A Website called Smodin.io

It will rewrite and check this for plagiarism and you won't get in trouble for plagiarism. Make sure you use your own situation in the ( ) and take out my answers.

mote1985 [20]3 years ago
5 0

Answer:

(a×b)×c = 0 means that vector c parallel to vector (a×b). But because   (a × b) ⊥ a and   (a -b) ⊥ b so

c ⊥ a and c ⊥ b.

Hope this helps, have a nice day! :D

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Step-by-step explanation:

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(1over5^2(3+2+5)^2=<br>i need helllllllllllllllllp pleaaaaaaassssseee​
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2500

Step-by-step explanation:

5^2(3+2+5)^2

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25(100)

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jOHN HAS 50 DOLLARS IN HIS WALLET, sUZANNAH HAS 30 DOLLARS WHAT PERCENTAGE OF JOUN'S MONEY DOES SUZANNAH HAVE?
ira [324]

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60%

Step-by-step explanation:


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Step-by-step explanation:

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3 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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