Please help me with this

Mathematics

1 answer:

tester [92]2 years ago

3 0

Answer:

16m

Step-by-step explanation:

AB would be double DE

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Why do you divide area of the circle by 2

solong [7]

Answer:

and two parts r equal btw but look below

Step-by-step explanation:

A circle is a geometric figure that needs only two parts to identify it and classify it: its center (or middle) and its radius (the distance from the center to any point on the circle). After you’ve chosen a point to be the center of a circle and know how far that point is from all the points that lie on the circle, you can draw a fairly decent picture.

3 0

2 years ago

What is the equation of the circle with center (-3.2, -2.1) and radius 4.3?

Ilya [14]

The equation of the circle is : $x^{2}$ + $y^{2}$ + 6.4 $x$ + 4.2 $y$ = 3.84

<h3>Meaning of a Circle</h3>

A circle is a loci or a continuous line that equidistant from the center to any point on the line. it drawn starting from a point and ending on that same point.

The equation of a circle is an equation used to find points on a circle so the circle can be drawn with accurate measurement. it can also be used to find the missing points.

In conclusion, The equation of the circle is : $x^{2}$ + $y^{2}$ + 6.4 $x$ + 4.2 $y$ = 3.84

Learn more about equation of a circle: brainly.com/question/1506955

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6 0

1 year ago

Use the value of the first integral I to evaluate the two given integrals. I = integral^3_0 (x^3 - 4x)dx = 9/4 A. integral^3_0 (

Troyanec [42]

Answer:

A) -9/2

B) 9/4

C) -9/2, same as A)

Step-by-step explanation:

We are given that $I=\int_0^3 x^3-4x dx=9/4$ . We use the properties of integrals to write the new integrals in terms of I.

A) $\int_0^3 8x-2x^3 dx=\int_0^3 -2(x^3-4x) dx=-2\int_0^3 x^3-4x dx=-2I=-9/2$ . We have used that ∫cf dx=c∫f dx.

B) $\int_3^0 4x - x^3 dx=-\int_0^3 (4x-x^3) dx=\int_0^3-(4x-x^3) dx=\int_0^3 x^3-4x dx=I=9/4$ . Here we used that reversing the limits of integration changes the sign of the integral.