Density = mass/volume
Volume = length x width x height
Volume = 2.5 x 2.5 x 2.5
= 15.625 cm^3
Density = 295/15.625
= 18.88 g/cm^3
The answer is
6X - 4 = 12 + 2X
Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft
Answer:
Last Option
.
Step-by-step explanation:
In this question we will do the factors of given two terms then we will do the common factors of all the terms given in answer to match with.
Common factors of 36h³ = 1×2×2×3×3×h×h×h
Common factors of
= 1×2×2×3×h×h×h×h×h×h
In these two terms greatest common factor Of these two terms is = 1×2×2×3×h×h×h = 12h³
Therefore the third term will be the number which has the greatest common factor = 12h³
So the given terms are
6h³ = 1×2×3×h×h×h
12h² = 1×2×2×3×h×h
= 1×2×3×5×h×h×h×h
= 1×2×2×2×2×3×h×h×h×h×h
Therefore the greatest common factor of the term which matches with 12h³ is 