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romanna [79]
3 years ago
14

If x = 5 cm, y = 12 cm, and z = 13 cm, what is the surface area of the geometric shape formed by this net?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

the answer is C.  210 sq. cm

Step-by-step explanation:

Find the area of the triangle

The area of one of the triangular faces can be found by using the formula below.  

a = 1/2 bh

a = 1/2 (5 cm) (12 cm)

a = 30 sq. cm

Since there are two triangular faces, multiply the area of one triangular face by 2. The area of two triangular faces is 60 cm2.

Next, find the area of each of the three rectangular faces using the formula, area = lw.

1st rectangle

a = lw

a =  (5 cm) (5 cm)

a = 25 sq. cm

2nd rectangle

a = lw

a = (5 cm) (12 cm)

a = 60 sq. cm

3rd rectangle

a = lw

a = (5 cm) (13 cm)

a - 65 sq. cm

Add the three rectangle areas to find a total of 150 sq. cm.

To find the surface area of the triangular prism, add the area of the two triangular faces to the area of the three rectangular faces.

60 sq. cm + 150 sq. cm = 210 sq. cm

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The sum of three consecutive odd numbers is 69. What are the three numbers?
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Answer:

21, 23, 25

Step-by-step explanation:

Ok, so this one may seem a little tricky, so I'll try to explain it as best as I can. :)

So because they are consecutive odd numbers, that means they are odd numbers that are one after the other. This means each number is 2 apart from the next. So by using this, we know that there is a difference of 6 between the highest and lowest number. Now let's try and make an equation:

3o + 6 = 69

Now in order to get O by itself we have to subtract 6 from both sides:

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Now we just have to divide by three on both sides:

o = 21

So now, we know that the lowest number is 21, but we have to add 2 to get 23, and then another 2 to get 25.

Hope this helps :)

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What is the scale factor of ABC to AXYZ?
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27/9 equals 3 . the answer is 3 .

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3 years ago
Is square root 1-cos^2theta=-sintheta true? if so, in which quadrants does angle theta terminate?
oksano4ka [1.4K]

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4 0
2 years ago
Find the area of a regular decagon with a perimeter of 60 ft.
Naddik [55]

Answer:

Area of a regular decagon with a perimeter of 60 ft. = 277 squared ft

Step-by-step explanation:

Decagon has 10 sides    So 60/10 = 6 (each side = 6ft )

The sum of the  interior angles of a decagon  is 1 440 degrees.

There are  10 equal isosceles triangles of base angles 72 degrees  in a decagon

Each isosceles triangle can subdivided into 2 right-angled triangles with height h and base length = (6/2) = 3 cm and base angle 72 degrees.

Height of right-angled triangle h = 3 tan 72 ft.

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