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romanna [79]
3 years ago
14

If x = 5 cm, y = 12 cm, and z = 13 cm, what is the surface area of the geometric shape formed by this net?

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

the answer is C.  210 sq. cm

Step-by-step explanation:

Find the area of the triangle

The area of one of the triangular faces can be found by using the formula below.  

a = 1/2 bh

a = 1/2 (5 cm) (12 cm)

a = 30 sq. cm

Since there are two triangular faces, multiply the area of one triangular face by 2. The area of two triangular faces is 60 cm2.

Next, find the area of each of the three rectangular faces using the formula, area = lw.

1st rectangle

a = lw

a =  (5 cm) (5 cm)

a = 25 sq. cm

2nd rectangle

a = lw

a = (5 cm) (12 cm)

a = 60 sq. cm

3rd rectangle

a = lw

a = (5 cm) (13 cm)

a - 65 sq. cm

Add the three rectangle areas to find a total of 150 sq. cm.

To find the surface area of the triangular prism, add the area of the two triangular faces to the area of the three rectangular faces.

60 sq. cm + 150 sq. cm = 210 sq. cm

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Hawick is 1515 miles south of Abbotsford, and Kelso is 1717 miles east of Abbotsford. What is the distance from Hawick to Kelso?
Mashcka [7]

Answer:

As per the statement:

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

Let  H represents  Hawick , A represents Abbotsford and K represents Kelso

See the diagram as shown below:

Distance of AH = 15 miles

Distance of AK = 17 miles.

We have to find the distance HK:

Using Pythagoras theorem;

\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2

then;

\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514

or

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For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right


It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
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</span><span>In notation we write respectively
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Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
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