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Yuliya22 [10]
2 years ago
11

How do I solve 16−(−5)=3(7−2)

Mathematics
2 answers:
densk [106]2 years ago
7 0

just solve both sides making 21=15 then see if the statement is true

this one isn't true :)

german2 years ago
6 0
Photo has the answer

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The point (3 , k) is a distance of 5 units from (0 , 1). Find the two possible values of k.
valkas [14]
D =√(x2-x1)^2 + (y2-y1)^2
......._____________
5 =√(3-0)^2 + (k-1)^2
.......__________
5 =√3^2 + (k-1)^2

25 = 9 + (k-1)^2

16 = k^2 - 2k + 1

k^2 -2k - 15 = 0

(k - 5)(k + 3) = 0

k - 5 = 0.....or.......(k + 3) = 0

k = 5.........or.......k = -3
7 0
3 years ago
What is x-4y=28 2x+y=2 on a graph
trasher [3.6K]
<span>-4y + x = 28
<span>  y + 2x = 2

hope this helped :)
alisa202</span></span>
3 0
4 years ago
6. A population of Florida fire ants grows at a rate of 8% a year. If there are 320 fire ants in
Vlada [557]

Answer: 1920

Step-by-step explanation:

3 0
3 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
3 years ago
I need help please?!!!!!
ozzi

Answer:

8

Step-by-step explanation:

plug in the number 4, it would be 5•4-12

Do 5•4=20

20-12=8

7 0
3 years ago
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