All categories

2 years ago

Find the values of v,w,x,y,z

Mathematics

1 answer:

vichka [17]2 years ago

7 0

Step-by-step explanation:

There isn't any equation given, so there isn't anything to do here

You might be interested in

A man is now twice as old as his son. fifteen years ago he was three times as old as his son was then. How old is the son now

Sergio039 [100]

Answer:

Step-by-step explanation:

25 years old.

3 0

3 years ago

Find the value of x in the diagram

Ksenya-84 [330]

Answer:

x = 21

Step-by-step explanation:

Based on the inscribed angle theorem, we would have:

120° = 2(3x - 3)°

Solve for x

120 = 2*3x - 2*3

120 = 6x - 6

Add 6 to both sides

120 + 6 = 6x

126 = 6x

Divide both sides by 6

126/6 = x

21 = x

x = 21

6 0

3 years ago

$325 tent; 15% discount<br> Helpppppp

kodGreya [7K]

276.25 hope that helps!!

8 0

3 years ago

Read 2 more answers

Pleasee help ASAP!! No links pleaseee!!!

Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(2-0)^2+(4-1)^2}$

$AB=\sqrt{(2)^2+(3)^2}$

$AB=\sqrt{4+9}$

$AB=\sqrt{13}$

Similarly,

$BC=\sqrt{(6-2)^2+(0-4)^2}$

$BC=\sqrt{(4)^2+(-4)^2}$

$BC=\sqrt{16+16}$

$BC=\sqrt{32}$

$BC=4\sqrt{2}$

Now, the length of the rectangle is $AB=\sqrt{13}$ and the width of the rectangle is $BC=4\sqrt{2}$ . So, the area of the rectangle is:

$A=length \times width$

$A=\sqrt{13}\times 4\sqrt{2}$

$A=4\sqrt{26}$

$A\approx 20$

Therefore, the area of the rectangle is 20 square units.

3 0

3 years ago

Sin2x=0..................

lapo4ka [179]

It would be 23 I’m pretty sure:)

5 0

3 years ago