Answer:
From the graph we can say that ant is moving faster than the ladybug
Slope of the ant's movement will be steeper than the ladybug
- Hence<u>, </u><u>line "</u>v" denotes the speed of ant and <u>line "</u>u" denotes the speed of ladybug.
Unit rate/slope of the graph is (distance traveled/elapsed time)
- <u>Unit rate of ant is 3/2 cm/sec</u> and <u>that of ladybug is 1 cm/sec.</u>
- Ant takes (12×2/3) =<u> </u><u>8</u><u> </u><u>sec</u> and ladybug takes (12×1) =<u> </u><u>12</u><u> </u><u>sec</u> to travel 12 cm.
Remember ant will take less time to travel a certain distance than ladybug.
Answer:
26°
Step-by-step explanation:
AC=tan 64
BC=x=sec 64
Using sine rule
(Sin 64)/tan 64 = (sin BAC)/sec 64
Cos 64 = (sin BAC)(cos 64)
Sin BAC= 1
BAC=90
ACB+ 64+90=180
ACB= 26°
Answer:
9x2x1 and 6x3x1
Step-by-step explanation:
This question has multiple answers to it. A sandbox of 18 cubic feet with a height of a foot is actually quite simple. If it is confusing I would try to visualize the sandbox. Since volume is b x h x w the first thing you should do is divide 18 by 1. This would be more important if the height was more than one. Now you just have to find two other numbers that can divide 18. 9x2=18 and 6x3=18 so two possible dimensions for the sandbox are 9x2x1 and 6x3x1
The population is increasing by 1500 each year and starts at 1970 population ( = 4800) so the equation is
y=1500x+4800
