All categories

3 years ago

How do you solve a/7+5/7=2/7

1 answer:

4 0

$\frac{a}{7} + \frac{5}{7} = \frac{2}{7} \\ \frac{a + 5}{7} = \frac{2}{7} \\ 7(\frac{a + 5}{7}) = 7(\frac{2}{7})$
a + 5 = 2
a + 5 - 5 = 2 - 5
a = -3

Hope this helps! :)

You might be interested in

G is proportional to the square of t. If t=2 and g=64, find g when t=3.5.

choli [55]

$If\ g\ is\ proportional\ to\ the\ t^2\ we\ have\ proportion\\\\
g=64\ \ \ \ ---\ \ \ t^2=2^2=4\\\\\
g=?\ \ \ ----t^2=(3,5)^ 2=12,25\\\\
4g=64*12,25\\\\
4g=784\ \ |:4\\\\g=196\\\\ Answer\ is\ g=196\ for\ t=3,5.$

4 0

3 years ago

An artificial soccer pitch is 91 meters long and 43 meters wide. If the cost of the pitch is AED 20 per square meter. What is th

Novosadov [1.4K]

The Cost of installing the artificial soccer pitch is $5360

A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are parallel and equal.

The soccer pitch us rectangle in shape. Hence:

Perimeter of soccer pitch = 2(length + width) = 2(91 + 43) = 268 meters

Cost of installing the pitch = $20 per meter * 268 meters = $5360

The Cost of installing the artificial soccer pitch is $5360

Find out more on perimeter at: brainly.com/question/16596982

6 0

1 year ago

What is the answer to 5n²/2n³×5n³

DanielleElmas [232]

5n(n^2+n+7)-3n(n^2+2n)

5n^3+5n^2+35n-3n^3-6n^2 

2n^3-n^2+35n 

n(2n^2-n+35)

4 0

2 years ago

The standard recipe for Hershey’s chocolate is 2/9 cups cocoa and 1/6 cups milk. If Hershey’s decided to pour a total of 14 cups

olya-2409 [2.1K]

Ok so if I understand this correctly then you have to find out what each one of them are then add them to get the total number of both of them. So this is the equation I did. The one circled on blue is the formula I made for the equation and then the green one is the answer. which is 5 4/9

I hope this helps.

3 0

2 years ago

What is the solution to the pair of simultaneous equations? 2x+y=5. 3x-2y=4

densk [106]

Answer:

(2, 1)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

2x + y = 5

3x - 2y = 4

Step 2: Rewrite Systems

Manipulate 1st equation

[Subtraction Property of Equality] Subtract 2x on both sides: y = 5 - 2x

Step 3: Solve for x

Substitution

Substitute in y [2nd Equation]: 3x - 2(5 - 2x) = 4
[Distributive Property] Distribute -2: 3x - 10 + 4x = 4
[Addition] Combine like terms: 7x - 10 = 4
[Addition Property of Equality] Add 10 on both sides: 7x = 14
[Division Property of Equality] Divide 7 on both sides: x = 2

Step 4: Solve for y

Substitute in x [Modified 1st Equation]: y = 5 - 2(2)
Multiply: y = 5 - 4
Subtract: y = 1

3 0

2 years ago