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ASHA 777 [7]
3 years ago
9

Uh yeah I need help can someone please explain to me please and thank you :)

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

53/36

Step-by-step explanation:

56/36 is already in it's simplest form

Ivanshal [37]3 years ago
5 0

Answer:

1 17/36

Step-by-step explanation:

Turn each fraction into their LCD (least common denominator)

5/9 turns into 20/36

11/12 turns into 33/36

add 20 + 33 = 53

Keep denominator  53/36

53/36 simplified as mixed number =  1 17/36

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The sketch was 36 inches wide
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F(x)= (x+9x2- 9x +15
Oduvanchick [21]

Answer:

10x+15

Step-by-step explanation:

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Which of the following pairs of numbers contains like fractions? A. 5⁄6 and 10⁄12 B. 3⁄2 and 2⁄3 C. 3 1⁄2 and 4 4⁄4 D. 6⁄7 and 1
ElenaW [278]
<h2>Hello!</h2>

The answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

<h2>Why?</h2>

To find which of the following pairs of numbers contains like fractions, we must remember that like fractions are the fractions that share the same denominator.

We are given two fractions that are like fractions. Those fractions are:

Option A.

\frac{5}{6} and \frac{10}{12}

We have that:

\frac{10}{12}=\frac{5}{6}

So, we have that the pairs of numbers

\frac{5}{6}

and

\frac{5}{6}

Share the same denominator, which is equal to 6, so, the pairs of numbers contains like fractions.

Option D.

\frac{6}{7} and 1\frac{5}{7}

We have that:

1\frac{5}{7}=1+\frac{5}{7}=\frac{7+5}{7}=\frac{12}{7}

So, we have that the pair of numbers

\frac{6}{7}

and

\frac{12}{7}

Share the same denominator, which is equal to 7, so, the pairs of numbers constains like fractions.

Also, we have that the other given options are not like fractions since both pairs of numbers do not share the same denominator.

The other options are:

\frac{3}{2},\frac{2}{3}

and

3\frac{1}{2},4\frac{4}{4}

We can see that both pairs of numbers do not share the same denominator so, they do not contain like fractions.

Hence, the answers are:

A.

\frac{5}{6} and \frac{10}{12}

D.

\frac{6}{7} and 1\frac{5}{7}

Have a nice day!

3 0
3 years ago
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
Whitepunk [10]

Answer: \mu=2.88\ \&\ \sigma^2=0.115

Step-by-step explanation:

Given : The probability of a correct classification of any part is : p=0.96

sample size : n= 3

The formula to find the mean and variance for binomial distribution is given by :-

\mu=np\\\\\sigma^2=np(1-p)

Let the random variable X denote the number of parts that are correctly classified.

The, for the given situation, we have

\mu=3(0.96)=2.88\\\\\sigma^2=(3)(0.96)(1-0.96)=0.1152\approx0.115

Hence, the mean and variance of X are 2.88 and 0.115 respectively.

4 0
3 years ago
a shopkeeper sold a certain number ( a two-digit number)of toys all priced at a certain value (also a two-digit number when expr
Makovka662 [10]

The answer is 91 toys sold, make the number ab where a is the 10th digit and b is the first digit. The value is 10a + b that can expressed as 10 (3) + 4 = 34

Let the price of each item: xy

10x + y

He accidentally reversed the digits to: 10b + a toys sold at 10y + x rupees per toy. To get use the formula, he sold 10a + b toys but thought he sold 10b + a toys. The number of toys that he thought he left over was 72 items more than the actual amount of toys left over. So he sold 72 more toys than he thought:

10a + b =10b + a +72

9a = 9b + 72

a = b + 8

The only numbers that could work are a = 9 and b = 1 since a and b each have to be 1 digit numbers. He reversed the digits and thought he sold 19 toys. So the actual number of toys sold was 10a + b = 10 (9) + 1 = 91 toys sold. By checking, he sold 91 – 19 = 72 toys more than the amount that he though the sold. As a result, the number of toys he thought he left over was 72 more than the actual amount left over as was stated in the question.

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3 0
3 years ago
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