What you don't want is the value of r(t) becoming negative. Surely that would represent water escaping the reservoir.
How big can (t) get before water actually starts escaping the reservoir?
Essentially, to figure this out r(t) would have to be equal to 0.
700 - 40t = 0
40t=700
t=700/40=17.5
So the first answer is 17.5 seconds. After this amount of time has elapsed the reservoir will start to lose water as r(t) would become negative.
---------------
The reservoir had the least amount of water in it before it was being filled. That was when t=0. The volume of water in the reservoir wasn't negatively impacted as not enough water had escaped it during the 17.5 to 30 second period.
Answer:
The value of x is 3.
Step-by-step explanation:
Matthew earned 7500 of 15000, which is exactly half the total amount, meaning that the fraction corresponding to his earnings is 1/2.
Rate of 5:2:x, with number 5 corresponding to Matthew, mean that his fraction of the earnings, in function of x is given by:
Both fractions are equal, so:
Applying cross multiplication:
The value of x is 3.
Answer:
x = -6
x = 2
Step-by-step explanation:
x² + 4 - 12 = 0
= (x + 6)(x - 2)
x + 6 = 0
x = -6
x - 2 = 0
x = 2
1.5 cleaner / 12 cups of water
or
1.5 cleaner : 12 cups of water
to reduce this ratio of 1.5:12, we need to divide both by the same number
1.5 divided by 1.5 is 1
12 divided by 1.5 is 8
So the ratio of cleaner to water is 1:8 in its simplest form or 1 part cleaner to 8 parts water.
Hope this helps!! :)
I'm Unsure, But Here's What I Found.
9.99×65=649.35
10.68×65=694.2
((10.68÷9.99)−1)×100=6.9%
