Question

Alex draws a diagonal in a rectangle that is 4 inches long and 3 inches wide. What is the area of one of two triangles that are formed?

Answer 1

Answer:

3.975 square inches

Step-by-step explanation:

Step 1

We find the length of the triangle

We solve using Pythagoras Theorem

Diagonal² = Length² + Width²

Diagonal = 4 inches

Width = 3 inches

Length² = Diagonal² - Width²

Length = √Diagonal² - Width²

Length = √4² - 3²

Length = √16 - 9

Length = √(7)

Length = 2.6457513111 inches

Length = 2.65 inches

Step 2

Area of Triangle = 1/2 × Base × Height

Base = Length = 2.65 inches

Height = Width = 3 inches

=1/2 × 2.65 inches × 3 inches

= 3.975 square inches

Therefore, the area of one of the triangles that are formed is 3.975 square inches