Answer:
-2/3
Step-by-step explanation:
in y=mx+b, m= the slope
and if you were graphing, you would put 2 on the y axis and use the rise over run strategy for the slope
hope this helped:)
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Replace ‘x’ with what ever number and then add 2, because if you make x a 1 then you would get a three. the equation goes from (x+2)=y to (1+2)=3 so make x whatever you want and then add 2 and you’ll get your ‘y’
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
12 vertices are on the polyhedron
